4x^2=16x+15

Solution for 4x^2=16x+15 equation:

4x^2=16x+15

We move all terms to the left:

4x^2-(16x+15)=0

We get rid of parentheses

4x^2-16x-15=0

a = 4; b = -16; c = -15;
Δ = b2-4ac
Δ = -162-4·4·(-15)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{31}}{2*4}=\frac{16-4\sqrt{31}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{31}}{2*4}=\frac{16+4\sqrt{31}}{8}
$